How do you solve for x in $L = Ax + (1 + B)x$ ?

Question

1842 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-01T13:15:28

$color(blue)(x) = L / (A+ 1 +B )$

$L =Acolor(blue)(x)+(1+B)color(blue)(x$

$L =Ax+ color(blue)(x) + Bcolor(blue)(x$

$x$ is common to all three terms of the R.H.S. so we take it out as a common term.

$L =color(blue)(x) (A+ 1 +B )$

$color(blue)(x) = L / (A+ 1 +B )$

How do you solve for x in L = Ax + (1 + B)xL = Ax + (1 + B)x?