What is the $pH$ $"pH"$ for $2.5 \times 10^{- 6} M$ $2.5 xx 10^(-6) "M"$ $HCl$ $"HCl"$ ?

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What is the $pH$ $"pH"$ for $2.5 \times 10^{- 6} M$ $2.5 xx 10^(-6) "M"$ $HCl$ $"HCl"$ ?

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Answer 1 · 2016-06-02T02:52:58

$p H = 5.60$ $pH=5.60$

Explanation:

HCl is a strong acid that fully ionizes when dissolved in water according to the following equation:

$H C l + H_{2} O \to H_{3} O^{+} + C l^{-}$ $HCl + H_2O -> H_3O^+ + Cl^-$

Having 1:1 ratio $=> [H_3O^+] = 2.5xx10^-6\ M$

$pH = -log [H_3O^+]$
$pH = -log(2.5xx10^-6)$
$pH = 5.60$

Note that the contribution of the autoionization of $H_2O$ to $[H_3O^+]$ is small (in the range of $10^-7 M$ ) that is why it is neglected. If it was not, it may contribute about one-tenth or so to the $"pH"$ .

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