How do you simplify #sqrt 2 times sqrt 2#?

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Answer 1 · 2016-06-03T04:41:51

2

#sqrt(a) * sqrt(b) = sqrt(a*b)#

so in our case:

#sqrt(2) * sqrt(2) = sqrt(2*2)#

which then simplifies into:

#sqrt(4)#

which then can be further simplified into:

2

to double check this answer, #2*2 = 4# which is the same as #sqrt(4)#