How do you solve #abs(3x+5) =1#?

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Answer 1 · 2016-06-04T16:59:01

The solutions are #x=-2# and #x=-4/3#

The absolute value is defined as

#absa=a if a>=0# and #absa=-a if a<0#

Hence the above equation becomes

#abs(3x+5)=1=>3x+5=1 or 3x+5=-1#

Then we have two solutions

#3x+5=1=>3x=-4=>x=-4/3#

and

#3x+5=-1=>3x=-6=>x=-2#