How do you solve $6(x+3)+38=2$ ?

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Answer 1 · 2016-06-06T07:48:04

$color(green)(x = -9$

As we need to find the value of $x$ , we try to transpose all the other terms to the right hand side.

Transposing 38 to the right hand side, we get:

$6(x+3) = 2-38$

$6(x+3) = -36$

To eliminate 6, we can divide both sides by 6

$(cancel(6)(x+3))/cancel6 = -36/6$

$x + 3 = -6$

Transposing 3 to the right hand side, we get

$x = -6 - 3$

$color(green)(x = -9$

Test:
Try substituting the value of $x$ in the original equation and check if it's satisfied

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