What is the weight in grams of #3.36 * 10^23# molecules of copper sulfate #CuSO_4#?

Question

8140 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-07T11:54:37

#~=89.1 \ g#

Do the following conversions:

# "Molecules "-> \ "mol. "-> "grams"#

#3.36xx10^23\ "molecules "CuSO_4xx ( 1 \ mol. CuSO_4)/ ( 6.02xx10^23 \ "molecules "CuSO_4)#

#3.36xx10^23\ cancel("molecules "CuSO_4)xx( 1 \ mol. CuSO_4)/ ( 6.02xx10^23 \ cancel("molecules "CuSO_4 ))#

#= 0.558 \ mol.\ CuSO_4#

The molar mass of #CuSO_4 = 159.57 \ g/(mol)#

#0.558 \ mol. \ CuSO_4xx(159.57 \ g \ CuSO_4)/(1\ mol. \ CuSO_4)#

#0.558 \ cancel (mol. \ CuSO_4)xx(159.57 \ g \ CuSO_4)/(1\ cancel(mol. \ CuSO_4))#

#~=89.1 \ g#

Note that #CuSO_4# is copper (II) sulfate.