How do you solve $4 (2 x + 10) = 9 (4 x - 8)$ $4 (2x + 10) = 9 (4x - 8)$ ?

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Answer 1 · 2016-06-08T14:46:14

$x = 4$ $x = 4$

$4 (2 x + 10) = 9 (4 x - 8)$ $4(2x+10)=9(4x−8)$

$4 \cdot (2 x) + 4 \cdot (10) = 9 \cdot (4 x) + (9) \cdot (- 8)$ $4 * (2x) + 4 * (10)= 9 * (4x) + (9) * (-8)$

$8 x + 40 = 36 x - 72$ $8x + 40 = 36x - 72$

$72 + 40 = 36 x - 8 x$ $72 + 40= 36x - 8x$

$112 = 28 x$ $112= 28x$

$x = \frac{112}{28}$ $x = 112/28$

$x = 4$ $x = 4$

How do you solve 4(2x+10)=9(4x−8)4 (2x + 10) = 9 (4x - 8)?