How do you differentiate $-1/(r-2)^2$ ?

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Answer 1 · 2016-06-09T04:12:46

$d/(dr)(-1/(r-2)^2)=2/(r-2)^3$

In order to use the chain rule, let $u=r-2$ . Then $(du)/(dr)=1$ . We are now differentiating

$-1/(r-2)^2=-1/u^2=-u^-2$

with respect to r. Using the power rule, the derivative is

$d/(dr)(-u^-2)=2u^-3*(du)/(dr)=2u^-3=2(r-2)^-3=2/(r-2)^3$

How do you differentiate -1/(r-2)^2-1/(r-2)^2?