How do you find the domain and range of f(x) = x^2 + 5f(x)=x2+5?

1 Answer
Jun 9, 2016

Domain: x in (-oo, oo)x(,)
Range: f(x) in (5, oo)f(x)(5,)

Explanation:

The domain is easy. You can enter any real number without restriction i.e. x in RR or equivalently x in (-oo, oo).

The range is a little trickier, but you can arrive at the answer two ways. First, if you know the graph of the function, you would know that it is a parabola opening up with its vertex at (0,5). Hence f(x) in (5, oo).

graph{x^2+5 [-9.66, 10.34, -0.96, 9.04]}

Another way to think about the range is to consider what values x can be. Because the variable is squared and a positive number is being added, the output must always be positive. Additionally, the smallest value will be achieved when x=0. At this point, f(x)=5 and so f(x) in (5, oo)