How do you solve for y in $2 x + 3 y = 4$ $2x+3y=4$ ?

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Answer 1 · 2016-06-10T05:56:13

$y = \frac{4 - 2 x}{3}$ $y=(4-2x)/3$

Just take y on one side, and all other terms on the other side of equation.

$2 x + 3 y = 4$ $2x +3y =4$

Subtracting $2 x$ $2x$ from both sides.

$3 y = 4 - 2 x$ $3y=4-2x$

Dividing both sides by $3$ $3$

$y = \frac{4 - 2 x}{3}$ $y=(4-2x)/3$

How do you solve for y in 2x+3y=42x+3y=42x+3y=4?