Strontium Hydroxide ionizes in water to produce the strontium ion and the hydroxide ion. Note that #Sr(OH)_2# is slightly soluble in water.
# " "Sr(OH)_2 \ \ rightleftharpoons \ \ \ Sr^(2+) + \ \ \ 2OH^-#
#I " " 0.1475 \ M " " - " " -#
#C" " -x " "+x " "+ 2x#
#E" "0.1475-x " " x " " 2x#
#K_b=( [ OH^-]^2 [ Sr^(2+)])/([Sr(OH)_2]#
#K_b= ( (2x)^2*(x))/(0.1475-x)= 6.5xx10^-3#
Solve for #x#
# x = 0.05346 \ M#
# [ OH^-] = 2x= 2xx 0.05346 = 0.1069 M#
# -------------------#
In any aqueous solution, both ions #H_3O^+#and #OH^-# are present and they must satisfy the following condition:
#[H_3O^+] [ OH^-] = K_W#
#[H_3O^+] [ OH^-] = 1.0xx10^(-14)#
# -------------------#
#[OH^-] = 0.1069 \ M # ( determined)
#[H_3O^+] = (1.0xx10^-14)/([ OH^-] )#
#[H_3O^+] = (1.0xx10^-14)/(0.1069 )#
#[H_3O^+] = 9.355^-14 \ M#
#-------------------#
#pH =- log [H_3O^+]#
#pH =- log [\ 3.955^-14 \]#
#pH = 13.0290#
#pOH =- log [\ OH^-\]#
# pOH =- log [\ 0.1069\ ]#
#pOH = 0.9710#
