Question

What is the norm or `<-7 ,6,-1 >`?

Answer 1

`sqrt86`

Explanation:

Let `x=(x_1,x_2,....,x_n)` be any vector in an n-dimensional vector space X.
Then the norm of `x` is given by

`||x||=sqrt(x_1^2+x_2^2+.....+x_n^2)`.

So in this particular case we work in a 3-dimesnional vector space and get that

`||(-7;6;1)||=sqrt((-7)^2+6^2+(-1)^2`

`=sqrt86`