What is $3 a - (m - 4 n^{2})$ $3a - (m-4n^2)$ when $a = - 1, m = - 3$ $a = -1, m = -3$ , and $n = 2$ $n = 2$ ?

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What is $3 a - (m - 4 n^{2})$ $3a - (m-4n^2)$ when $a = - 1, m = - 3$ $a = -1, m = -3$ , and $n = 2$ $n = 2$ ?

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Answer 1 · 2016-06-13T12:54:04

$16$ $16$

Explanation:

This involves substitution, but as soon as there are negative signs involved, work very carefully.

$a = - 1, m = - 3, n = 2$ $a = -1, m = -3, n = 2$
$3 a - (m - 4 n^{2}) = 3 (- 1) - [(- 3) - (4 {(2)}^{2})]$ $3a -(m - 4n^2) = 3(-1) - [(-3)-(4(2)^2)]$

$= - 3 - [- 3 - 4 \times 4)]$ $= -3 - [-3 - 4xx4)]$

$= - 3 - [- 19] = - 3 + 19$ $= -3 - [-19] = -3 +19$

$= 16$ $=16$

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What is $3 a - (m - 4 n^{2})$ $3a - (m-4n^2)$ when $a = - 1, m = - 3$ $a = -1, m = -3$ , and $n = 2$ $n = 2$ ?

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What is 3a−(m−4n2)3a - (m-4n^2) when a=−1,m=−3a = -1, m = -3, and n=2n = 2?

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What is $3 a - (m - 4 n^{2})$ $3a - (m-4n^2)$ when $a = - 1, m = - 3$ $a = -1, m = -3$ , and $n = 2$ $n = 2$ ?