Question

How do you find the period of `f(x) = 3sin (x/2 + pi)`?

Answer 1

period`=4pi`

Explanation:

The standard form of the sine wave function is

`y=asin(bx+c)+d`

where amplitude `= |a|` , period `=(2pi)/b`

phase shift `=-c/b" and d , the vertical shift"`

here `b=1/2rArr" period"=(2pi)/(1/2)=4pi`