How do you solve $(\frac{2 t - 1}{3 t + 4}) = 2$ $((2t-1)/(3t+4)) = 2$ ?

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Answer 1 · 2016-06-19T09:00:15

$t = - \frac{9}{4}$ $color(green)(t = -9/4$

$\frac{2 t - 1}{3 t + 4} = 2$ $(2t - 1) / (3t + 4) = 2$

$(2 t - 1) = 2 \cdot (3 t + 4)$ $(2t - 1) = color(blue)(2) * (3t + 4 )$

$2$ $color(blue)(2)$ is multiplied with both terms within the second bracket.

$(2 t - 1) = 2 \cdot (3 t) + 2 \cdot (4)$ $(2t - 1) = color(blue)(2) * (3t) + color(blue)(2) *( 4 )$

$2 t - 1 = 6 t + 8$ $2t - 1 = 6t + 8$

$2 t - 6 t = 8 + 1$ $2t - 6t = 8 +1$

$- 4 t = 9$ $- 4t = 9$

$- t = \frac{9}{- 4}$ $-t = 9/ (-4)$

$t = - \frac{9}{4}$ $color(green)(t = -9/4$

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