How do you graph and find the #x# and #y# intercepts of #y = -1/2x + 6#?

1 Answer
Jun 20, 2016

X intercept: #X = 12#

Y intercept: #Y = 6#

Explanation:

Here's the graph for your function.
Read further below for solution steps.
graph{-1/2x+6 [-10, 10, -5, 5]}
Starting with the easiest one to deduce, the Y intercept is simply the point on the graph where the function intersects with the Y axis, at #x = 0#.

So just substitute #x# with #0#, solve, and you'll have your #y# value.

#y=-1/2(color(red)(0))+6#
#y=6#

The X intercept is the point where the function intersects with the X axis, at #y = 0#.

In this case, we wish to get the #x# value, so we first need to isolate #x# to get the answer:

#color(red)(0)-6=-1/2x+6-6#

#{-6}/{-1/2}={-1/2x}/{-1/2}#

#12=x#

#therefore x=12#

You can now compare to the graph, and see that the results are exactly as those that were calculated.