A ball with a mass of $280 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $12 (kg)/s^2$ and was compressed by $7/3 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2016-06-20T05:55:13

$"spring constant "(k)=12"kg"/s^2$
$"compressed length "(x)=7/3m$
Potential energy of spring= $1/2kx^2$

$"Mass of the ball "(m)=280g=0.28kg$

By principle of conservation of energy

Energy of spring=energy of the ball

$1/2*k*x^2=mgh$
$=>h=1/2(kx^2)/(mg)$
$=>h=1/2*12*(7/3*7/3)*1/(0.28*9.8)$
$=>h=1/(3*0.028)=11.9m$

A ball with a mass of 280 g280 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 12 (kg)/s^212 (kg)/s^2 and was compressed by 7/3 m7/3 m when the ball was released. How high will the ball go?