How do you solve #x^2 + 9x + 9 = 0#? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer 冠廷 李. Jun 20, 2016 #x=(-9+-3sqrt5)/2# Explanation: #x^2+9x=-9# #x^2+9x+81/4=-9+81/4# #(x+9/2)^2=45/4# #(x+9/2)=(+-3sqrt5)/2# #x=(-9+-3sqrt5)/2# Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 3790 views around the world You can reuse this answer Creative Commons License