How do you solve 4x-2(1-x)=2(3x-2)?

1 Answer
Jun 23, 2016

You cannot, it is a contradiction.

Explanation:

Two ways:

1.
4x - 2(1-x) = 2(3x-2) factor out 2

2(2x - (1-x)) = 2(3x-2) divide by 2

2x - 1 + x = 3x - 2 simplify

3x - 1 = 3x -2 + 1 to both sides (by this point we can see it is a contradiction)

3x = 3x - 1 divide by 3

x ≠ x - (1/3) impossible / false statment

2.
4x-2(1-x) = 2(3x-2) expand brackets

4x - 2 + 2x = 6x - 4 combine like terms (simplify)

6x - 2 = 6x-4 divide by 2 (by this point we can see it is a contradiction)

3x - 1 = 3x -2 + 1

3x = 3x - 1 divide by 3

x ≠ x - (1/3) impossible / false statment

In both ways we see a statement which is false . You can never have x = x - (1/3) or any similar statement - it's like saying 1 = 1 - (1/3). It is just not true. Therefore the original statement is a contradiction and cannot be solved.