How do you solve for r in $\frac{1}{2} r + 3 s = 1$ $1/2r +3s=1$ ?

Question

3607 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-23T12:09:57

$r = 2 - 6 s$ $color(blue)(r= 2 - 6s$

$\frac{1}{2} r + 3 s = 1$ $1/2color(blue)(r) +3s = 1$

$\frac{1}{2} r = 1 - 3 s$ $1/2color(blue)(r)= 1 - 3s$

The main goal here is to isolate $r .$ $color(blue)(r).$

$r = (1 - 3 s) \times \frac{2}{1}$ $color(blue)(r)= (1 - 3s) xx color(green)(2)/1$

$r = (1) \times 2 + (- 3 s) \times 2$ $color(blue)(r)= (1 ) xx color(green)(2) + (- 3s) xx color(green)( 2$

$r = 2 - 6 s$ $color(blue)(r= 2 - 6s$

How do you solve for r in 12r+3s=11/2r +3s=1?