Question

Question #bf75f

Answer 1

Answering about a center and a radius of this circle.
Center is at point `O(13/2, -1/2)`
Radius is `3/2sqrt(2)`

Explanation:

If the question is about a center and a radius of this circle, we know that the center lies right in the middle of the endpoints of a diameter. Therefore, the coordinates of a center `O(X,Y)` are
`X = (5+8)/2 = 13/2`
`Y = (1+(-2))/2 = -1/2`

The radius `R` is a distance from a center `O(13/2, -1/2)` to any of two endpoints of a diameter. We'll take the point `(5,1)`:
`R = sqrt((13/2-5)^2+(-1/2-1)^2)=3/2sqrt(2)`