How do you solve $6 x + y = 23$ $6x + y = 23$ and $x + 5 y = 28$ $x + 5y = 28$ ?

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Answer 1 · 2016-06-25T13:36:18

The solution for the system of equations is :
$x = 3, y = 5$ $color(green)(x = 3 , y=5$

$6 x + y = 23$ $color(blue)(6x) + y = 23$ ...............equation $(1)$ $(1)$

$x + 5 y = 28$ $x + 5y = 28$ , multiplying by $6 :$ $6:$

$6 x + 30 y = 168$ $color(blue)(6x) + 30y = 168$ ........equation $(2)$ $(2)$

Subtracting equation $1$ $1$ from $2 :$ $2:$

$cancelcolor(blue)(6x) + 30y = 168$
$-cancelcolor(blue)(6x) - y = -23$

$29y= 145$

$y = 145/29$

$color(green)(y = 5$

Finding $x$ from equation $2:$

$x + 5y = 28$

$x = 28 - 5y$

$x = 28 - 5 xx 5$

$x = 28 - 25$

$color(green)(x = 3$

How do you solve 6x + y = 236x+y=236x + y = 23 and x + 5y = 28x+5y=28x + 5y = 28?