How do you simplify $2 + 6 (8) \div 4$ $2+6(8) div4$ using PEMDAS?

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Answer 1 · 2016-06-26T18:12:06

Begin with the number in parenthesis

Begin with Parenthesis and Division

(8) is in parenthesis, multiply (8) by 6

$(8) \cdot 6 = 48$ $(8)*6=48$

We now have $2 + 48 \div 4$ $2+48-:4$

Next is division, divide 48 by 4

$48 \div 4 = 12$ $48-:4=12$

We now have 2+12

End with addition, adds 2 to 12.

$12 + 2 = 14$ $12+2=14$

$2 + 6 (8) \div 4 = 2 + 48 \div 4 = 2 + 12 = 14$ $2+6(8)-:4=2+48-:4=2+12=14$

How do you simplify 2+6(8)÷42+6(8) div4 using PEMDAS?