How do you solve the system of equations #8x+7y = 18# and #3x-5y=22#?

1 Answer
Jun 27, 2016

#x = 244/61# and #y = (-122)/61#

Explanation:

Equation 1 => #8x + 7y = 18#

Equation 2 => #3x - 5y = 22#

Multiply Equation 1 by 5 and Equation 2 by 7, we get

Equation 3 => #40x + 35y = 90#

Equation 4 => #21x - 35y = 154#

Adding 3 & 4, we get #61x + 0y = 90 + 154# => #x = 244/61#

Solve in a similar manner to determine y.

Multiply Equation 1 by 3 and Equation 2 by 8, we get

Equation 5 => #24x + 21y = 54#

Equation 6 => #24x - 40y = 176#

Subtract Equation 6 from 5, we get:

#21y + 40 y = 54 -176# => #61 y = -122# => #y = (-122)/61#