How do you solve the system of equations 8x+7y = 18 and 3x-5y=22?

1 Answer
Jun 27, 2016

x = 244/61 and y = (-122)/61

Explanation:

Equation 1 => 8x + 7y = 18

Equation 2 => 3x - 5y = 22

Multiply Equation 1 by 5 and Equation 2 by 7, we get

Equation 3 => 40x + 35y = 90

Equation 4 => 21x - 35y = 154

Adding 3 & 4, we get 61x + 0y = 90 + 154 => x = 244/61

Solve in a similar manner to determine y.

Multiply Equation 1 by 3 and Equation 2 by 8, we get

Equation 5 => 24x + 21y = 54

Equation 6 => 24x - 40y = 176

Subtract Equation 6 from 5, we get:

21y + 40 y = 54 -176 => 61 y = -122 => y = (-122)/61