How do you simplify #(7sqrt5)^2#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer jags Jun 27, 2016 #245# Explanation: # (a* b)^2# can be expanded as # (a^2 * b^2) # So, #(7* sqrt 5)^ 2# can be written as #7^2 * (sqrt 5)^ 2# => #49* 5# => #245# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1423 views around the world You can reuse this answer Creative Commons License