If #x^3 = 1/4x#, what is the possible value of x?

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Answer 1 · 2016-06-27T23:51:57

#x = 0 or x = -1/2 or x = 1/2#

Factorize the above equation to get the possible values of x.

#x^3 = 1/4*x#

=> #4x^3 = x#

=> #4x^3 - x = 0#

=> #x ( 4x^2 - 1) = 0#

=> #x ( (2x)^2 - (1)^2) = 0#

=> #x ( 2x+ 1) ( 2x -1 ) = 0#

#x = 0 or x = -1/2 or x = 1/2#