How do you solve # (5x - 1)^2 = 4/25#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer jags Jun 28, 2016 #x = 3/25# or #x = 7/25# Explanation: #(5x-1)^2 = 4/25# => #(5x-1)^2 = (2/5)^2# => #5x -1 = +- 2/5# => #5x -1 = + 2/5# means #5x= (2/5 +1)# => #x = 7/25# => #5x -1 = - 2/5# means #5x= (-2/5 +1)# => #x = 3/25# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 2329 views around the world You can reuse this answer Creative Commons License