Suppose x varies inversely with y. If X = 10 when y = 5 how do you find x when y = 14?

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Suppose x varies inversely with y. If X = 10 when y = 5 how do you find x when y = 14?

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Answer 1 · 2016-06-28T16:17:09

Construct a variation equation and solve for $x$ $x$ to get $x = \frac{25}{7}$ $x=25/7$ .

Explanation:

When we say " $x$ $x$ varies inversely with $y$ $y$ ", we mean that when $x$ $x$ increases, $y$ $y$ decreases, and vice versa. Mathematically, this is expressed as:
$y = \frac{k}{x}$ $y=k/x$
Where $k$ $k$ is referred to as the constant of variation.

We are told $x = 10$ $x=10$ when $y = 5$ $y=5$ , so:
$5 = \frac{k}{10}$ $5=k/10$
$\to 10 \cdot 5 = k \to 50 = k$ $->10*5=k->50=k$

Our equation is:
$y = \frac{50}{x}$ $y=50/x$

If $y = 14$ $y=14$ , then
$14 = \frac{50}{x}$ $14=50/x$
$\to x = \frac{50}{14} = \frac{25}{7}$ $->x=50/14=25/7$

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Suppose x varies inversely with y. If X = 10 when y = 5 how do you find x when y = 14?

1 Answer

Explanation:

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