How do you simplify #sqrt((75a)/49)#?
1 Answer
Jun 30, 2016
Explanation:
=
#sqrt 5^2# *#sqrt (3a) / sqrt (7^2)# =
#5/7* sqrt(3a)#
=
#sqrt 5^2# *#sqrt (3a) / sqrt (7^2)# =
#5/7* sqrt(3a)#