How do you solve $x^{2} + 5 x + 6 = 0$ $x^2 + 5x + 6 = 0$ algebraically?

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Answer 1 · 2016-07-01T00:45:35

$x = - 3$ $x = -3$ OR $x = - 2$ $x = -2$

We have: $x^{2} + 5 x + 6 = 0$ $x^2 +5x+6=0$

Step 1: Factor
Since we have already set the quadratic equal to 0, we can just factor.
$(x + 3) (x + 2) = 0$ $(x+3)(x+2) = 0$

Step 2: Set each factor equal to 0
$x + 3 = 0$ $x+3 = 0$ OR $x + 2 = 0$ $x+2 = 0$
$x = - 3$ $x = -3$ OR $x = - 2$ $x = -2$

How do you solve x^2 + 5x + 6 = 0x2+5x+6=0x^2 + 5x + 6 = 0 algebraically?