How do you solve $7(-3y + 2) = 8(3y - 2)$ ?

Question

3696 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-01T04:54:37

$7(-3y+2)=8(3y-2)$

First, distribute the seven and eight.

$-21y+14=24y-16$

Next, add $21y$ to both sides.

$14=45y-16$

And then, add sixteen to both sides to isolate the $y$ .

$30=45y$

Divide 30 by 45 to solve for $y$

$y=30/45$

Simplify! - Both are divisible by 5.

$y=6/9$

Both are divisible by 3.

$y=2/3$

How do you solve 7(-3y + 2) = 8(3y - 2) 7(-3y + 2) = 8(3y - 2) ?