How do you evaluate $cot (690)$ $cot (690)$ ?

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Answer 1 · 2016-07-02T04:43:48

$- \sqrt{3}$ $-sqrt 3$

$690 = 720 - 30 = 4 (180) - 30$ $690=720-30=4(180)-30$ .So, $690°$ is in the 4th quadrant

and, therefore, $cot$ is negative.

And so, $cot 690°=cot(4(180°)-30°)=-cot 30°=-sqrt 3$ .

How do you evaluate cot (690)cot(690)cot (690)?