How do you find the domain and range of $sqrt(2x - 3)$ ?

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Answer 1 · 2016-07-03T07:59:37

Hi
For the domain: $2x-3>=0$
This term must be greater than, or equal to zero
as it is under a root.
and hence

$2x>=3 rArr x>=3/2$

As we have 'equal to', we will use a closed bracket [

Hence the domain will be [3/2,infinity)

Infinity will be in open bracket ).

How do you find the domain and range of sqrt(2x - 3)sqrt(2x - 3)?