Question

How do you find the domain and range of `sqrt(2x - 3)`?

Answer 1

Hi
For the domain: `2x-3>=0`
This term must be greater than, or equal to zero
as it is under a root.
and hence

`2x>=3 rArr x>=3/2`

As we have 'equal to', we will use a closed bracket [

Hence the domain will be [3/2,infinity)

Infinity will be in open bracket ).