How many moles of copper are equivalent to $3.44 \cdot 10^{23}$ $3.44*10^23$ atoms of copper?

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Answer 1 · 2016-07-03T14:02:56

$0.571 mol.$ $0.571 " mol."$

First you need to find the conversion factor. We know that 1 mol. contains Avogadro's number of atoms and therefore our conversion factor will be:

$\ 1 " mol." = 6.02xx10^23 " atoms"$

$3.44xx10^23 \ "atoms" xx (1 \ "mol.")/(6.02xx10^23 \ "atoms")$

$3.44xx10^23\ cancel("atoms") xx (1 \ "mol.")/(6.02xx10^23 \ cancel("atoms"))$

$0.571 " mol."$

How many moles of copper are equivalent to 3.44*10^233.44⋅10233.44*10^23 atoms of copper?