A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is #33 # and the height of the cylinder is #14 #. If the volume of the solid is #225 pi#, what is the area of the base of the cylinder?

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Answer 1 · 2016-07-04T10:44:53

#(75pi)/13#

Assume the radius of the cylinder/cone as r, height of cone as #h_1#, height of cylinder as #h_2#

Volume of the cone part of solid = #(pi*r^2*h_1)/3#

Volume of the cylinder part of solid = # pi*r^2 * h_2#

What we have is:

#h_1# = 33,#h_2# = 14

#(pi*r^2*h_1)/3# + # pi*r^2 * h_2# = #225*pi#

#(pi*r^2*33)/3# + # pi*r^2 * 14# = #225*pi#

# pi*r^2 * 11# + # pi*r^2 * 28# = #225*pi#

# 39.pi*r^2 # = #225*pi#

# r^2 # = #225/39# = #75/13#

Area of the base of the cylinder = #pi*r^2# = #pi*75/13# = #(75pi)/13#