Question #fef12

Question

Question #fef12

1 Answer

Impact of this question

2041 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-04T14:01:08

$C r_{2} {(S O_{4})}_{3} ∙ 12 H_{2} O (s) + H_{2} O (l) \to 2 {[C r {(H_{2} O)}_{6}]}_{6}^{3+} (a q) + 3 S O_{4}^{2-} (a q)$ $Cr_2(SO_4)_3 • 12H_2O(s) + H_2O(l) -> 2[Cr(H_2O)_6]^"3+"(aq) + 3SO_4^"2-"(aq)$

Explanation:

Then the Cr(III) hexaaquocomplex undergoes a partial acid hydrolysis:

${[C r {(H_{2} O)}_{6}]}_{6}^{3+} (a q) + H_{2} O (l) ⇌ {[C r {(H_{2} O)}_{5} (O H)]}_{5}^{2+} (a q) + H_{3} O^{+} (a q)$ $[Cr(H_2O)_6]^"3+"(aq) + H_2O(l) rightleftharpoons [Cr(H_2O)_5(OH)]^"2+"(aq) + H_3O^+(aq)$

Science

Math

Humanities

... and beyond

Question #fef12

1 Answer

Explanation:

Related questions

Impact of this question