How do you convert $(6, 6)$ $(6, 6)$ into polar form?

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How do you convert $(6, 6)$ $(6, 6)$ into polar form?

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Answer 1 · 2016-07-06T01:11:51

Make use of a few formulas to get $(6, 6) \to (6 \sqrt{2}, \frac{π}{4})$ $(6,6)->(6sqrt(2),pi/4)$ .

Explanation:

The desired conversion from $(x, y) \to (r, θ)$ $(x,y)->(r,theta)$ can be accomplished with the use of the following formulas:
$r = \sqrt{x^{2} + y^{2}}$ $r=sqrt(x^2+y^2)$
$θ = {tan}^{- 1} (\frac{y}{x})$ $theta=tan^(-1) (y/x)$

Using these formulas, we obtain:
$r = \sqrt{{(6)}^{2} + {(6)}^{2}} = \sqrt{72} = 6 \sqrt{2}$ $r=sqrt((6)^2+(6)^2)=sqrt(72)=6sqrt(2)$
$θ = {tan}^{- 1} (\frac{6}{6}) = {tan}^{- 1} 1 = \frac{π}{4}$ $theta=tan^(-1)(6/6)=tan^(-1)1=pi/4$

Thus $(6, 6)$ $(6,6)$ in rectangular coordinates corresponds to $(6 \sqrt{2}, \frac{π}{4})$ $(6sqrt(2),pi/4)$ in polar coordinates.

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How do you convert $(6, 6)$ $(6, 6)$ into polar form?

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