How do you solve $(x-2)/2 <=3$ ?

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Answer 1 · 2016-07-07T07:58:58

$x <= 8$

Solve the equation the same way as a linear equation except at any stage if you multiply by a negative change the sign around. So..

$(x - 2)/2 <= 3$

Multiply both sides by 2, since we are multiplying by a positive leave the sign:

$x - 2 <= 6$

Then add 2 to both sides:

$x <= 8$

How do you solve (x-2)/2 <=3(x-2)/2 <=3?