Question

Using the following reaction, if 1.75 moles of nitrogen gas are reacted with excess hydrogen gas, how many moles of `NH_3` will be produced? `N_2 + 3H_2 -> 2NH_3`?

Answer 1

3.5 moles

Explanation:

Simply write out the mole ratio of the known and unknown components:

`(n(NH_3))/(n(N_2))=2/1`

`n(NH_3)=2n(N_2)=2xx1.75mol=3.5mol`