How do you find a standard form equation for the line (2,-1) (0,-4)?

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Answer 1 · 2016-07-08T16:19:14

$y = \frac{3}{2} x - 4$ $y = 3/2 x - 4$

The equation of the straight line is given by:

$y = a x + b$ $y= ax +b$

Where a is the slope and b is the y-intercept.

First start by finding the slope. The slope is determined using the following formula:

$a = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $a= (y_2 - y_1)/(x_2 - x_1)$

$a = \frac{- 4 - (- 1)}{0 - 2}$ $a = (-4 - (-1))/(0 - 2)$

$a = \frac{- 3}{- 2}$ $a = (-3)/-2$

$a = \frac{3}{2}$ $a = 3/2$

0 and -4 is a point on the graph. Use its coordinates to find the y-intercept.

$y = \frac{3}{2} x + b$ $y = 3/2 x + b$

$- 4 = \frac{3}{2} \times 0 + b$ $-4 = 3/2 xx 0 + b$

$b = - 4$ $b= -4$

graph{3/2 *x - 4 [-10.54, 9.46, -12.28, -2.28]}