How do you multiply #-(12-4x)+8(10-x)#?

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Answer 1 · 2016-07-09T05:37:52

In this problem, it is easier to distribute the signs first.

#-(12-4x)+8(10-x)#

#=-12+4x+80-8x#

Collecting like terms (the constants and every number with the variable #x#) gives us

#-12+80+4x-8x#

#=68-4x#

And since #68# and #4# are both divisbly by #4#, we can simplify further, giving us

#=4(17-x)#