How do you solve #10^(2x)+3=8#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Alexander Jul 9, 2016 #10^(2x)+3=8# #10^(2x)=5# #2x * log(10) = log(5)# #2x = log(5) / log(10)# #x = (log(5) / log(10)) * 1/2# #x = log(5) / (2 log(10))# Explanation: Remember that #log_b (x^r) = r log_b (x)#. Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 2549 views around the world You can reuse this answer Creative Commons License