Question

How do you solve `3tanx-sqrt3=0` and find all solutions in the interval `[0,2pi)`?

Answer 1

`(pi/6`,`(7*pi)/6)`

Explanation:

`3*tan x-sqrt3=0`
`3*tan x =sqrt3`
`tan x =sqrt3/3`
`arctan(sqrt3/3)=pi/6`
The tan function has a period of `pi`, so it will repeat at `pi+pi/6` or `(7*pi)/6`