A group of 62 randomly selected students have a mean score of 28.3 on a standardized placement test. The population SD for all students taking the test is σ=3.4. What is the 90 percent confidence interval for the mean score?

1 Answer
Jul 13, 2016

Population mean is likely to fall between 29.005 and 27.595

Explanation:

Given -

¯x=28.3
n=62
σ=3.4
z score for 90% confidence interval 1.64
SE=σn=3.462=3.47.87=0.43

90% confidence interval is defined by the formula

μ=¯x+(SE×z) --------upper limit
μ=28.3+(0.43×1.64)=28.3+0.705=29.005

μ=¯x(SE×z) --------Lower limit
μ=28.3(0.43×1.64)=28.30.705=27.595

Look at the diagram

Sample means are normally distributed around the population mean μ

An interval is developed as 29.005 and 27.595. There is 90% chance for the population mean to fall in this interval.