A group of 62 randomly selected students have a mean score of 28.3 on a standardized placement test. The population SD for all students taking the test is σ=3.4. What is the 90 percent confidence interval for the mean score?
1 Answer
Jul 13, 2016
Population mean is likely to fall between
Explanation:
Given -
¯x=28.3
n=62
σ=3.4
z score for 90% confidence interval1.64
SE=σ√n=3.4√62=3.47.87=0.43
90% confidence interval is defined by the formula
μ=¯x+(SE×z) --------upper limit
μ=28.3+(0.43×1.64)=28.3+0.705=29.005
μ=¯x−(SE×z) --------Lower limit
μ=28.3−(0.43×1.64)=28.3−0.705=27.595
Sample means are normally distributed around the population mean
An interval is developed as