How do you solve #y/6+12=10#?

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Answer 1 · 2016-07-14T07:27:34

#y = -12#

First we need to get the integers on one side of the equation:

#y/6 + 12 - 12 = 10 - 12#

#y/6 = -2#

Now we need to multiply both sides of the equation by #6# so that #y# will be on its own:

#(y/6)6 = (-2)6#

Therefore,

#y = -12#