How do you solve #7(w+1)=5(2w-3)+1#?

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Answer 1 · 2016-07-14T07:38:35

#w = 7#

Start by expanding both sides of the equation:

#7(w + 1) = 5(2w - 3) + 1#

#= 7w + 7 = 10w - 15 + 1#

Then we simplify by getting the terms with #w# on one side and the integers on the other:

#7w - 7w + 7 + 14 = 10w - 7w - 14 + 14#

Therefore,

#21 = 3w#

By dividing both sides by #3# we see that:

#21/3 = 3w/3 = 7 = w#

You can verify this by putting #7# back into the original equations:

#7(7 + 1) = 5(14 - 3) + 1#

#= 7(8) = 5(11) + 1#

#= 56 = 55 + 1#