How do you find the midpoint of S(4,-1) and T(6,0)?

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How do you find the midpoint of S(4,-1) and T(6,0)?

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Answer 1 · 2016-07-14T11:22:40

By midpoint formula,
Midpoint of ST = $(5, - 0.5)$ $(5, -0.5)$

Explanation:

S = (4,-1) where 4 = $x_{1}$ $x_"1"$ and -1 = $y_{1'}$ $y_"1'"$
T = (6,0) where 6 = $x_{2}$ $x_"2"$ and 0 = $y_{2}$ $y_"2"$

Midpoint Formula => $(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$ $( (x_"1" + x_"2")/2 , (y_"1" + y_"2")/2)$

Substituting the values of $x_{1}, y_{1'}, x_{2}, y_{2}$ $x_"1",y_"1'",x_"2",y_"2"$ in the formula gives

$(\frac{4 + 6}{2}, \frac{- 1 + 0}{2})$ $( (4 + 6)/2 , (-1+0)/2)$

$(5, - 0.5)$ $( 5 , -0.5)$

Answer 2 · 2016-07-14T11:27:45

Mid point "M" is at $(5, - \frac{1}{2})$ $(5, -1/2)$

Explanation:

Mid point "M" is at $(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}) = (\frac{4 + 6}{2}, \frac{- 1 + 0}{2}) or (5, - \frac{1}{2})$ $((x_1+x_2)/2,(y_1+y_2)/2)=((4+6)/2,(-1+0)/2) or (5, -1/2)$ [Ans]

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How do you find the midpoint of S(4,-1) and T(6,0)?

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