How do you solve $log(x+7) - log(x-7)=1$ ?

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Answer 1 · 2016-07-16T07:21:09

$x=77/9$

As $log(x+7)−log(x−7)=1$ , we have

$log((x+7)/(x−7))=1 = log 10$

$(x+7)/(x−7)=10$ or

$x+7=10x-70$ or

$10x-x=77$ or

$9x=77$ or

$x=77/9$

How do you solve log(x+7) - log(x-7)=1log(x+7) - log(x-7)=1?