Question

How do you solve `sin(x/2)-1=0` between the interval `0<=x<8pi`?

Answer 1

`x = pi` or `x=5 pi`

Explanation:

Since `0<= x<8pi`, we have `0<= x/2<4pi`. Since `sin(x/2)=1`, the only allowed values of `x/2` in the interval `[0,4pi)` are `x/2 = pi/2` and `x/2={5pi}/2`.