How do you solve #(25y^2)^(1/2) #?
1 Answer
Jul 17, 2016
Explanation:
Anything to the
#(25y^2)^(1/2) = sqrt(25y^2)#
Find the square root. Note that
#sqrt25 times sqrt(y^2)#
#5 times y#
#5y#
There can also be a negative answer. Every value has a negative root, because when you multiply two negative numbers you end up with the same positive number.
Example:
So, the square root of
The other possible solution: